${\displaystyle {\begin{array}{l}\nabla \cdot \mathbf {D} =\rho \\\nabla \cdot \mathbf {B} =0\\\nabla \times \mathbf {E} =-{\frac {\partial \mathbf {B} }{\partial t}}\\\nabla \times \mathbf {H} =\mathbf {J} +{\frac {\partial \mathbf {D} }{\partial t}}\end{array}}}$

In your article, replace the image with:

<math>\begin{array}{l}
    \nabla\cdot\mathbf{D}= \rho \\
    \nabla\cdot\mathbf{B}=0 \\
    \nabla\times\mathbf{E}=-\frac{\partial\mathbf{B} }{\partial t} \\
    \nabla\times\mathbf{H}= \mathbf{J}+\frac{\partial\mathbf{D} }{\partial t} 
\end{array}</math>

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